133042400352433 has 16 divisors (see below), whose sum is σ = 156473889477696. Its totient is φ = 111520880735040.

The previous prime is 133042400352413. The next prime is 133042400352439. The reversal of 133042400352433 is 334253004240331.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133042400352433 is a prime.

It is a super-3 number, since 3×133042400352433³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133042400352392 and 133042400352401.

It is not an unprimeable number, because it can be changed into a prime (133042400352439) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 512751466 + ... + 513010867.

It is an arithmetic number, because the mean of its divisors is an integer number (9779618092356).

Almost surely, 2^{133042400352433} is an apocalyptic number.

133042400352433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

133042400352433 is a deficient number, since it is larger than the sum of its proper divisors (23431489125263).

133042400352433 is a wasteful number, since it uses less digits than its factorization.

133042400352433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1025763264.

The product of its (nonzero) digits is 311040, while the sum is 37.

Adding to 133042400352433 its reverse (334253004240331), we get a palindrome (467295404592764).

The spelling of 133042400352433 in words is "one hundred thirty-three trillion, forty-two billion, four hundred million, three hundred fifty-two thousand, four hundred thirty-three".