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133042433 is a prime number
BaseRepresentation
bin1111110111000…
…01000100000001
3100021100020220112
413323201010001
5233024324213
621111321105
73203561546
oct773410401
9307306815
10133042433
116910a827
1238680195
1321742544
1413952bcd
15ba2eea8
hex7ee1101

133042433 has 2 divisors, whose sum is σ = 133042434. Its totient is φ = 133042432.

The previous prime is 133042411. The next prime is 133042447. The reversal of 133042433 is 334240331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 124701889 + 8340544 = 11167^2 + 2888^2 .

It is a cyclic number.

It is not a de Polignac number, because 133042433 - 210 = 133041409 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 133042399 and 133042408.

It is not a weakly prime, because it can be changed into another prime (133042033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66521216 + 66521217.

It is an arithmetic number, because the mean of its divisors is an integer number (66521217).

Almost surely, 2133042433 is an apocalyptic number.

It is an amenable number.

133042433 is a deficient number, since it is larger than the sum of its proper divisors (1).

133042433 is an equidigital number, since it uses as much as digits as its factorization.

133042433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 23.

The square root of 133042433 is about 11534.4021518239. The cubic root of 133042433 is about 510.5011516213.

Adding to 133042433 its reverse (334240331), we get a palindrome (467282764).

The spelling of 133042433 in words is "one hundred thirty-three million, forty-two thousand, four hundred thirty-three".