Base | Representation |
---|---|
bin | 1100000110011010011011… |
… | …1010101010000111000011 |
3 | 1202002212202112012001221101 |
4 | 3001212212322222013003 |
5 | 3220434213403013103 |
6 | 44143530104035231 |
7 | 2542130210016301 |
oct | 301464672520703 |
9 | 52085675161841 |
10 | 13304314110403 |
11 | 426a367521a98 |
12 | 15aa56ba62b17 |
13 | 75678c506c74 |
14 | 33dd0a0c5271 |
15 | 181120965a1d |
hex | c19a6eaa1c3 |
13304314110403 has 4 divisors (see below), whose sum is σ = 13352344125520. Its totient is φ = 13256284095288.
The previous prime is 13304314110401. The next prime is 13304314110449. The reversal of 13304314110403 is 30401141340331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13304314110403 - 21 = 13304314110401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13304314110401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24015007143 + ... + 24015007696.
It is an arithmetic number, because the mean of its divisors is an integer number (3338086031380).
Almost surely, 213304314110403 is an apocalyptic number.
13304314110403 is a deficient number, since it is larger than the sum of its proper divisors (48030015117).
13304314110403 is an equidigital number, since it uses as much as digits as its factorization.
13304314110403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 48030015116.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 13304314110403 its reverse (30401141340331), we get a palindrome (43705455450734).
The spelling of 13304314110403 in words is "thirteen trillion, three hundred four billion, three hundred fourteen million, one hundred ten thousand, four hundred three".
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