Base | Representation |
---|---|
bin | 11000110010000000… |
… | …00001111000100001 |
3 | 1021100012110111110101 |
4 | 30121000001320201 |
5 | 204221402340001 |
6 | 10040102102401 |
7 | 650460011161 |
oct | 143100017041 |
9 | 37305414411 |
10 | 13304340001 |
11 | 5707a53617 |
12 | 26b371aa01 |
13 | 134045c044 |
14 | 902d4c5a1 |
15 | 52d01ba01 |
hex | 319001e21 |
13304340001 has 2 divisors, whose sum is σ = 13304340002. Its totient is φ = 13304340000.
The previous prime is 13304339963. The next prime is 13304340107. The reversal of 13304340001 is 10004340331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12117606400 + 1186733601 = 110080^2 + 34449^2 .
It is an emirp because it is prime and its reverse (10004340331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13304340001 - 211 = 13304337953 is a prime.
It is not a weakly prime, because it can be changed into another prime (13314340001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6652170000 + 6652170001.
It is an arithmetic number, because the mean of its divisors is an integer number (6652170001).
Almost surely, 213304340001 is an apocalyptic number.
It is an amenable number.
13304340001 is a deficient number, since it is larger than the sum of its proper divisors (1).
13304340001 is an equidigital number, since it uses as much as digits as its factorization.
13304340001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 13304340001 its reverse (10004340331), we get a palindrome (23308680332).
The spelling of 13304340001 in words is "thirteen billion, three hundred four million, three hundred forty thousand, one".
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