Base | Representation |
---|---|
bin | 11110010000000010010110… |
… | …011001100000011111110011 |
3 | 122110001211100101220211200002 |
4 | 132100002112121200133303 |
5 | 114414240421114330003 |
6 | 1150543150314020215 |
7 | 40011033140631116 |
oct | 3620022631403763 |
9 | 573054311824602 |
10 | 133043430230003 |
11 | 39434446a25577 |
12 | 12b0885b71766b |
13 | 5930c31a16027 |
14 | 24bd49d05c57d |
15 | 105ab719eda88 |
hex | 7900966607f3 |
133043430230003 has 2 divisors, whose sum is σ = 133043430230004. Its totient is φ = 133043430230002.
The previous prime is 133043430229991. The next prime is 133043430230027. The reversal of 133043430230003 is 300032034340331.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (300032034340331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133043430230003 - 26 = 133043430229939 is a prime.
It is a super-2 number, since 2×1330434302300032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (133043430239003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66521715115001 + 66521715115002.
It is an arithmetic number, because the mean of its divisors is an integer number (66521715115002).
Almost surely, 2133043430230003 is an apocalyptic number.
133043430230003 is a deficient number, since it is larger than the sum of its proper divisors (1).
133043430230003 is an equidigital number, since it uses as much as digits as its factorization.
133043430230003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23328, while the sum is 29.
Adding to 133043430230003 its reverse (300032034340331), we get a palindrome (433075464570334).
The spelling of 133043430230003 in words is "one hundred thirty-three trillion, forty-three billion, four hundred thirty million, two hundred thirty thousand, three".
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