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133044045551 = 211362964527
BaseRepresentation
bin111101111101000001…
…0110000011011101111
3110201102001211210002122
41323322002300123233
54134433233424201
6141041455343155
712416645504504
oct1737202603357
9421361753078
10133044045551
115147299365a
1221950221abb
13c71373b111
1466218994ab
1536da207e1b
hex1efa0b06ef

133044045551 has 4 divisors (see below), whose sum is σ = 133107012192. Its totient is φ = 132981078912.

The previous prime is 133044045523. The next prime is 133044045581. The reversal of 133044045551 is 155540440331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133044045551 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133044045581) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31480151 + ... + 31484376.

It is an arithmetic number, because the mean of its divisors is an integer number (33276753048).

Almost surely, 2133044045551 is an apocalyptic number.

133044045551 is a deficient number, since it is larger than the sum of its proper divisors (62966641).

133044045551 is an equidigital number, since it uses as much as digits as its factorization.

133044045551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 62966640.

The product of its (nonzero) digits is 72000, while the sum is 35.

Adding to 133044045551 its reverse (155540440331), we get a palindrome (288584485882).

The spelling of 133044045551 in words is "one hundred thirty-three billion, forty-four million, forty-five thousand, five hundred fifty-one".

Divisors: 1 2113 62964527 133044045551