133054220402333 has 4 divisors (see below), whose sum is σ = 133085817229248. Its totient is φ = 133022623575420.

The previous prime is 133054220402291. The next prime is 133054220402387. The reversal of 133054220402333 is 333204022450331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133054220402333 - 2¹² = 133054220398237 is a prime.

It is a super-3 number, since 3×133054220402333³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133054220402293 and 133054220402302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133054220402533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15798407141 + ... + 15798415562.

It is an arithmetic number, because the mean of its divisors is an integer number (33271454307312).

Almost surely, 2^{133054220402333} is an apocalyptic number.

It is an amenable number.

133054220402333 is a deficient number, since it is larger than the sum of its proper divisors (31596826915).

133054220402333 is an equidigital number, since it uses as much as digits as its factorization.

133054220402333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31596826914.

The product of its (nonzero) digits is 155520, while the sum is 35.

Adding to 133054220402333 its reverse (333204022450331), we get a palindrome (466258242852664).

The spelling of 133054220402333 in words is "one hundred thirty-three trillion, fifty-four billion, two hundred twenty million, four hundred two thousand, three hundred thirty-three".