Base | Representation |
---|---|
bin | 11110010000001100011010… |
… | …010100110011100101000001 |
3 | 122110002212020022020001202011 |
4 | 132100030122110303211001 |
5 | 114414430032240241140 |
6 | 1150552134314052521 |
7 | 40011564641260504 |
oct | 3620143224634501 |
9 | 573085208201664 |
10 | 133054233524545 |
11 | 39438a90120673 |
12 | 12b0a97571a141 |
13 | 5931c63c6aac8 |
14 | 24bdc05b6713b |
15 | 105b0a5184cea |
hex | 79031a533941 |
133054233524545 has 16 divisors (see below), whose sum is σ = 160190547834240. Its totient is φ = 106093625462784.
The previous prime is 133054233524521. The next prime is 133054233524557. The reversal of 133054233524545 is 545425332450331.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 133054233524545 - 219 = 133054233000257 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 32464059 + ... + 36332128.
It is an arithmetic number, because the mean of its divisors is an integer number (10011909239640).
Almost surely, 2133054233524545 is an apocalyptic number.
It is an amenable number.
133054233524545 is a deficient number, since it is larger than the sum of its proper divisors (27136314309695).
133054233524545 is an equidigital number, since it uses as much as digits as its factorization.
133054233524545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 68797464.
The product of its (nonzero) digits is 12960000, while the sum is 49.
Adding to 133054233524545 its reverse (545425332450331), we get a palindrome (678479565974876).
The spelling of 133054233524545 in words is "one hundred thirty-three trillion, fifty-four billion, two hundred thirty-three million, five hundred twenty-four thousand, five hundred forty-five".
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