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133054402412111 = 2811025946154909
BaseRepresentation
bin11110010000001100100100…
…011001000011111001001111
3122110002212200002000102221012
4132100030210121003321033
5114414430404004141421
61150552203145555435
740011602061634205
oct3620144431037117
9573085602012835
10133054402412111
1139439067493374
1212b0aa021a5b7b
135931c8cc5098b
1424bdc2036b075
15105b0b4de595b
hex790324643e4f

133054402412111 has 8 divisors (see below), whose sum is σ = 133540924201200. Its totient is φ = 132567972953920.

The previous prime is 133054402412089. The next prime is 133054402412119. The reversal of 133054402412111 is 111214204450331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 133054402412111 - 214 = 133054402395727 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133054402412119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20194676 + ... + 25960233.

It is an arithmetic number, because the mean of its divisors is an integer number (16692615525150).

Almost surely, 2133054402412111 is an apocalyptic number.

133054402412111 is a deficient number, since it is larger than the sum of its proper divisors (486521789089).

133054402412111 is a wasteful number, since it uses less digits than its factorization.

133054402412111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 46165449.

The product of its (nonzero) digits is 11520, while the sum is 32.

Adding to 133054402412111 its reverse (111214204450331), we get a palindrome (244268606862442).

The spelling of 133054402412111 in words is "one hundred thirty-three trillion, fifty-four billion, four hundred two million, four hundred twelve thousand, one hundred eleven".

Divisors: 1 281 10259 2882779 46154909 12969529429 473503211431 133054402412111