Base | Representation |
---|---|
bin | 11110010000001100100110… |
… | …011010110001001100101110 |
3 | 122110002212202102222221002211 |
4 | 132100030212122301030232 |
5 | 114414430441210224004 |
6 | 1150552210402441034 |
7 | 40011602653641625 |
oct | 3620144632611456 |
9 | 573085672887084 |
10 | 133054436414254 |
11 | 394390846a7713 |
12 | 12b0aa1166317a |
13 | 5931c96cc74a4 |
14 | 24bdc24a9c6bc |
15 | 105b0b7db0504 |
hex | 7903266b132e |
133054436414254 has 4 divisors (see below), whose sum is σ = 199581654621384. Its totient is φ = 66527218207126.
The previous prime is 133054436414203. The next prime is 133054436414293. The reversal of 133054436414254 is 452414634450331.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 133054436414198 and 133054436414207.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33263609103562 + ... + 33263609103565.
It is an arithmetic number, because the mean of its divisors is an integer number (49895413655346).
Almost surely, 2133054436414254 is an apocalyptic number.
133054436414254 is a deficient number, since it is larger than the sum of its proper divisors (66527218207130).
133054436414254 is an equidigital number, since it uses as much as digits as its factorization.
133054436414254 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66527218207129.
The product of its (nonzero) digits is 8294400, while the sum is 49.
The spelling of 133054436414254 in words is "one hundred thirty-three trillion, fifty-four billion, four hundred thirty-six million, four hundred fourteen thousand, two hundred fifty-four".
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