133055022143453 has 4 divisors (see below), whose sum is σ = 140057918045760. Its totient is φ = 126052126241148.

The previous prime is 133055022143431. The next prime is 133055022143471. The reversal of 133055022143453 is 354341220550331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133055022143453 - 2¹⁰ = 133055022142429 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 133055022143453.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133055022143413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3501447951125 + ... + 3501447951162.

It is an arithmetic number, because the mean of its divisors is an integer number (35014479511440).

Almost surely, 2^{133055022143453} is an apocalyptic number.

It is an amenable number.

133055022143453 is a deficient number, since it is larger than the sum of its proper divisors (7002895902307).

133055022143453 is an equidigital number, since it uses as much as digits as its factorization.

133055022143453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7002895902306.

The product of its (nonzero) digits is 648000, while the sum is 41.

Adding to 133055022143453 its reverse (354341220550331), we get a palindrome (487396242693784).

The spelling of 133055022143453 in words is "one hundred thirty-three trillion, fifty-five billion, twenty-two million, one hundred forty-three thousand, four hundred fifty-three".