Base | Representation |
---|---|
bin | 1100000110011110110111… |
… | …1010011001101100011101 |
3 | 1202002222211112110222200101 |
4 | 3001213231322121230131 |
5 | 3220444133314204001 |
6 | 44144244213501101 |
7 | 2542201552231126 |
oct | 301475572315435 |
9 | 52088745428611 |
10 | 13305505225501 |
11 | 426a91890a435 |
12 | 15aa842941791 |
13 | 75691c20a2b8 |
14 | 33ddc038104d |
15 | 1811902e8a01 |
hex | c19ede99b1d |
13305505225501 has 4 divisors (see below), whose sum is σ = 13305571573504. Its totient is φ = 13305438877500.
The previous prime is 13305505225499. The next prime is 13305505225517. The reversal of 13305505225501 is 10552250550331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13305505225501 - 21 = 13305505225499 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13305505255501) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32872275 + ... + 33274576.
It is an arithmetic number, because the mean of its divisors is an integer number (3326392893376).
Almost surely, 213305505225501 is an apocalyptic number.
It is an amenable number.
13305505225501 is a deficient number, since it is larger than the sum of its proper divisors (66348003).
13305505225501 is an equidigital number, since it uses as much as digits as its factorization.
13305505225501 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66348002.
The product of its (nonzero) digits is 112500, while the sum is 37.
Adding to 13305505225501 its reverse (10552250550331), we get a palindrome (23857755775832).
The spelling of 13305505225501 in words is "thirteen trillion, three hundred five billion, five hundred five million, two hundred twenty-five thousand, five hundred one".
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