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133100033000000 = 26561112100003
BaseRepresentation
bin11110010000110111000100…
…001011111100001001000000
3122110021020110011000110221212
4132100313010023330021000
5114421202331422000000
61151025151103505252
740015105616346143
oct3620670413741100
9573236404013855
10133100033000000
1139456452799430
1212b178178b8228
1359363826aa141
1424c210c66605a
15105c385d94c35
hex790dc42fc240

133100033000000 has 196 divisors, whose sum is σ = 360159571460976. Its totient is φ = 48400008000000.

The previous prime is 133100032999933. The next prime is 133100033000057. The reversal of 133100033000000 is 330001331.

It is an unprimeable number.

It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 4949999 + ... + 17050001.

Almost surely, 2133100033000000 is an apocalyptic number.

133100033000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133100033000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (180079785730488).

133100033000000 is an abundant number, since it is smaller than the sum of its proper divisors (227059538460976).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133100033000000 is an frugal number, since it uses more digits than its factorization.

133100033000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12100056 (or 12100021 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 14.

Adding to 133100033000000 its reverse (330001331), we get a palindrome (133100363001331).

The spelling of 133100033000000 in words is "one hundred thirty-three trillion, one hundred billion, thirty-three million", and thus it is an aban number.