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133100041322221 is a prime number
BaseRepresentation
bin11110010000110111000100…
…101011101011111011101101
3122110021020110201200021220021
4132100313010223223323231
5114421202341034302341
61151025152002122141
740015106050160161
oct3620670453537355
9573236421607807
10133100041322221
1139456457462aa6
1212b1781a650351
13593638433212c
1424c210d7d0ca1
15105c38698a9d1
hex790dc4aebeed

133100041322221 has 2 divisors, whose sum is σ = 133100041322222. Its totient is φ = 133100041322220.

The previous prime is 133100041322197. The next prime is 133100041322233. The reversal of 133100041322221 is 122223140001331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121703678099721 + 11396363222500 = 11031939^2 + 3375850^2 .

It is a cyclic number.

It is not a de Polignac number, because 133100041322221 - 25 = 133100041322189 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133100041322291) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66550020661110 + 66550020661111.

It is an arithmetic number, because the mean of its divisors is an integer number (66550020661111).

Almost surely, 2133100041322221 is an apocalyptic number.

It is an amenable number.

133100041322221 is a deficient number, since it is larger than the sum of its proper divisors (1).

133100041322221 is an equidigital number, since it uses as much as digits as its factorization.

133100041322221 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 133100041322221 its reverse (122223140001331), we get a palindrome (255323181323552).

The spelling of 133100041322221 in words is "one hundred thirty-three trillion, one hundred billion, forty-one million, three hundred twenty-two thousand, two hundred twenty-one".