13310012013 has 4 divisors (see below), whose sum is σ = 17746682688. Its totient is φ = 8873341340.

The previous prime is 13310012003. The next prime is 13310012039. The reversal of 13310012013 is 31021001331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13310012013 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13310011983 and 13310012001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13310012003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2218335333 + ... + 2218335338.

It is an arithmetic number, because the mean of its divisors is an integer number (4436670672).

Almost surely, 2^13310012013 is an apocalyptic number.

It is an amenable number.

13310012013 is a deficient number, since it is larger than the sum of its proper divisors (4436670675).

13310012013 is an equidigital number, since it uses as much as digits as its factorization.

13310012013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4436670674.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 13310012013 its reverse (31021001331), we get a palindrome (44331013344).

The spelling of 13310012013 in words is "thirteen billion, three hundred ten million, twelve thousand, thirteen".