Base | Representation |
---|---|
bin | 11110010000110111001010… |
… | …100100101000001101001101 |
3 | 122110021020201121121111212220 |
4 | 132100313022210220031031 |
5 | 114421203041333311440 |
6 | 1151025205452045553 |
7 | 40015111360106613 |
oct | 3620671244501515 |
9 | 573236647544786 |
10 | 133100140135245 |
11 | 394564a8213758 |
12 | 12b178477638b9 |
13 | 593639b94b58a |
14 | 24c211c9936b3 |
15 | 105c3904a88d0 |
hex | 790dca92834d |
133100140135245 has 16 divisors (see below), whose sum is σ = 212964157065600. Its totient is φ = 70985430455744.
The previous prime is 133100140135231. The next prime is 133100140135301. The reversal of 133100140135245 is 542531041001331.
It is a cyclic number.
It is not a de Polignac number, because 133100140135245 - 27 = 133100140135117 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 81094770 + ... + 82719779.
It is an arithmetic number, because the mean of its divisors is an integer number (13310259816600).
Almost surely, 2133100140135245 is an apocalyptic number.
133100140135245 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
133100140135245 is a deficient number, since it is larger than the sum of its proper divisors (79864016930355).
133100140135245 is a wasteful number, since it uses less digits than its factorization.
133100140135245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 163868724.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 133100140135245 its reverse (542531041001331), we get a palindrome (675631181136576).
The spelling of 133100140135245 in words is "one hundred thirty-three trillion, one hundred billion, one hundred forty million, one hundred thirty-five thousand, two hundred forty-five".
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