Base | Representation |
---|---|
bin | 10011010111100110011… |
… | …101100110010010011111 |
3 | 11201020120110210110121121 |
4 | 103113212131212102133 |
5 | 133301402410210101 |
6 | 2455242545511411 |
7 | 165106463224540 |
oct | 23274635462237 |
9 | 4636513713547 |
10 | 1331011413151 |
11 | 47352a274962 |
12 | 195b61042567 |
13 | 9868ab94554 |
14 | 485c80724c7 |
15 | 249517370a1 |
hex | 135e676649f |
1331011413151 has 8 divisors (see below), whose sum is σ = 1521622682240. Its totient is φ = 1140516839448.
The previous prime is 1331011413139. The next prime is 1331011413157. The reversal of 1331011413151 is 1513141101331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1331011413151 - 215 = 1331011380383 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1331011413157) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29149401 + ... + 29195026.
It is an arithmetic number, because the mean of its divisors is an integer number (190202835280).
Almost surely, 21331011413151 is an apocalyptic number.
1331011413151 is a deficient number, since it is larger than the sum of its proper divisors (190611269089).
1331011413151 is an equidigital number, since it uses as much as digits as its factorization.
1331011413151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58347693.
The product of its (nonzero) digits is 540, while the sum is 25.
Adding to 1331011413151 its reverse (1513141101331), we get a palindrome (2844152514482).
The spelling of 1331011413151 in words is "one trillion, three hundred thirty-one billion, eleven million, four hundred thirteen thousand, one hundred fifty-one".
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