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1331012123113 is a prime number
BaseRepresentation
bin10011010111100110100…
…000010011100111101001
311201020120112010112111111
4103113212200103213221
5133301403100414423
62455243013030321
7165106502242441
oct23274640234751
94636515115444
101331012123113
1147352a70a302
12195b613253a1
139868b08274a
14485c81b9121
152495182760d
hex135e68139e9

1331012123113 has 2 divisors, whose sum is σ = 1331012123114. Its totient is φ = 1331012123112.

The previous prime is 1331012123099. The next prime is 1331012123167. The reversal of 1331012123113 is 3113212101331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 711370791184 + 619641331929 = 843428^2 + 787173^2 .

It is an emirp because it is prime and its reverse (3113212101331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1331012123113 - 225 = 1330978568681 is a prime.

It is not a weakly prime, because it can be changed into another prime (1331012123183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665506061556 + 665506061557.

It is an arithmetic number, because the mean of its divisors is an integer number (665506061557).

Almost surely, 21331012123113 is an apocalyptic number.

It is an amenable number.

1331012123113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331012123113 is an equidigital number, since it uses as much as digits as its factorization.

1331012123113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 1331012123113 its reverse (3113212101331), we get a palindrome (4444224224444).

The spelling of 1331012123113 in words is "one trillion, three hundred thirty-one billion, twelve million, one hundred twenty-three thousand, one hundred thirteen".