Base | Representation |
---|---|
bin | 1100000110110000000110… |
… | …0101110000001100010111 |
3 | 1202010102202212102100101221 |
4 | 3001230001211300030113 |
5 | 3221033121330333442 |
6 | 44150331153431211 |
7 | 2542424303020051 |
oct | 301540145601427 |
9 | 52112685370357 |
10 | 13310130324247 |
11 | 4271881634599 |
12 | 15ab71386b507 |
13 | 7571a84a4713 |
14 | 3402dc7328d1 |
15 | 181361398467 |
hex | c1b01970317 |
13310130324247 has 2 divisors, whose sum is σ = 13310130324248. Its totient is φ = 13310130324246.
The previous prime is 13310130324209. The next prime is 13310130324349. The reversal of 13310130324247 is 74242303101331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13310130324247 - 211 = 13310130322199 is a prime.
It is a super-2 number, since 2×133101303242472 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13310137324247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655065162123 + 6655065162124.
It is an arithmetic number, because the mean of its divisors is an integer number (6655065162124).
Almost surely, 213310130324247 is an apocalyptic number.
13310130324247 is a deficient number, since it is larger than the sum of its proper divisors (1).
13310130324247 is an equidigital number, since it uses as much as digits as its factorization.
13310130324247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36288, while the sum is 34.
Adding to 13310130324247 its reverse (74242303101331), we get a palindrome (87552433425578).
The spelling of 13310130324247 in words is "thirteen trillion, three hundred ten billion, one hundred thirty million, three hundred twenty-four thousand, two hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •