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133101420100973 is a prime number
BaseRepresentation
bin11110010000111000010110…
…110111010011110101101101
3122110021101000211002111202222
4132100320112313103311231
5114421213202021212343
61151025540454125125
740015155161456252
oct3620702667236555
9573241024074688
10133101420100973
1139456aa4777975
1212b17b443507a5
135936543b9064c
1424c220097b429
15105c417a3ca68
hex790e16dd3d6d

133101420100973 has 2 divisors, whose sum is σ = 133101420100974. Its totient is φ = 133101420100972.

The previous prime is 133101420100933. The next prime is 133101420101011. The reversal of 133101420100973 is 379001024101331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70192442316649 + 62908977784324 = 8378093^2 + 7931518^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133101420100973 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133101420100903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66550710050486 + 66550710050487.

It is an arithmetic number, because the mean of its divisors is an integer number (66550710050487).

Almost surely, 2133101420100973 is an apocalyptic number.

It is an amenable number.

133101420100973 is a deficient number, since it is larger than the sum of its proper divisors (1).

133101420100973 is an equidigital number, since it uses as much as digits as its factorization.

133101420100973 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13608, while the sum is 35.

The spelling of 133101420100973 in words is "one hundred thirty-three trillion, one hundred one billion, four hundred twenty million, one hundred thousand, nine hundred seventy-three".