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133101447415231 is a prime number
BaseRepresentation
bin11110010000111000011000…
…011111100000010110111111
3122110021101002201111012220011
4132100320120133200112333
5114421213231014241411
61151025543311404051
740015155642600541
oct3620703037402677
9573241081435804
10133101447415231
1139457009133539
1212b17b51523627
135936549735029
1424c220444b691
15105c41a135c21
hex790e187e05bf

133101447415231 has 2 divisors, whose sum is σ = 133101447415232. Its totient is φ = 133101447415230.

The previous prime is 133101447415193. The next prime is 133101447415259. The reversal of 133101447415231 is 132514744101331.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133101447415231 is a prime.

It is a super-2 number, since 2×1331014474152312 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133101447415291) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66550723707615 + 66550723707616.

It is an arithmetic number, because the mean of its divisors is an integer number (66550723707616).

Almost surely, 2133101447415231 is an apocalyptic number.

133101447415231 is a deficient number, since it is larger than the sum of its proper divisors (1).

133101447415231 is an equidigital number, since it uses as much as digits as its factorization.

133101447415231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120960, while the sum is 40.

The spelling of 133101447415231 in words is "one hundred thirty-three trillion, one hundred one billion, four hundred forty-seven million, four hundred fifteen thousand, two hundred thirty-one".