Base | Representation |
---|---|
bin | 11000110010101100… |
… | …01101010110001010 |
3 | 1021100121101212221012 |
4 | 30121112031112022 |
5 | 204224344412442 |
6 | 10040430443522 |
7 | 650560305026 |
oct | 143126152612 |
9 | 37317355835 |
10 | 13310154122 |
11 | 5710264881 |
12 | 26b56635a2 |
13 | 1341716555 |
14 | 903a23386 |
15 | 52d7b9582 |
hex | 31958d58a |
13310154122 has 4 divisors (see below), whose sum is σ = 19965231186. Its totient is φ = 6655077060.
The previous prime is 13310154083. The next prime is 13310154127. The reversal of 13310154122 is 22145101331.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 10547495401 + 2762658721 = 102701^2 + 52561^2 .
It is not an unprimeable number, because it can be changed into a prime (13310154127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3327538529 + ... + 3327538532.
Almost surely, 213310154122 is an apocalyptic number.
13310154122 is a deficient number, since it is larger than the sum of its proper divisors (6655077064).
13310154122 is an equidigital number, since it uses as much as digits as its factorization.
13310154122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6655077063.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 13310154122 its reverse (22145101331), we get a palindrome (35455255453).
The spelling of 13310154122 in words is "thirteen billion, three hundred ten million, one hundred fifty-four thousand, one hundred twenty-two".
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