Base | Representation |
---|---|
bin | 11000110010101100… |
… | …01101010110111101 |
3 | 1021100121101220000002 |
4 | 30121112031112331 |
5 | 204224344413143 |
6 | 10040430444045 |
7 | 650560305131 |
oct | 143126152675 |
9 | 37317356002 |
10 | 13310154173 |
11 | 5710264918 |
12 | 26b5663625 |
13 | 1341716594 |
14 | 903a233c1 |
15 | 52d7b95b8 |
hex | 31958d5bd |
13310154173 has 2 divisors, whose sum is σ = 13310154174. Its totient is φ = 13310154172.
The previous prime is 13310154127. The next prime is 13310154181. The reversal of 13310154173 is 37145101331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13262516569 + 47637604 = 115163^2 + 6902^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13310154173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13310156173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655077086 + 6655077087.
It is an arithmetic number, because the mean of its divisors is an integer number (6655077087).
Almost surely, 213310154173 is an apocalyptic number.
It is an amenable number.
13310154173 is a deficient number, since it is larger than the sum of its proper divisors (1).
13310154173 is an equidigital number, since it uses as much as digits as its factorization.
13310154173 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3780, while the sum is 29.
The spelling of 13310154173 in words is "thirteen billion, three hundred ten million, one hundred fifty-four thousand, one hundred seventy-three".
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