1331016126541 has 2 divisors, whose sum is σ = 1331016126542. Its totient is φ = 1331016126540.

The previous prime is 1331016126529. The next prime is 1331016126547. The reversal of 1331016126541 is 1456216101331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 689381484100 + 641634642441 = 830290^2 + 801021^2 .

It is an emirp because it is prime and its reverse (1456216101331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1331016126541 - 2¹⁵ = 1331016093773 is a prime.

It is a super-2 number, since 2×1331016126541² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1331016126497 and 1331016126506.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1331016126547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665508063270 + 665508063271.

It is an arithmetic number, because the mean of its divisors is an integer number (665508063271).

Almost surely, 2^{1331016126541} is an apocalyptic number.

It is an amenable number.

1331016126541 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331016126541 is an equidigital number, since it uses as much as digits as its factorization.

1331016126541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 34.

The spelling of 1331016126541 in words is "one trillion, three hundred thirty-one billion, sixteen million, one hundred twenty-six thousand, five hundred forty-one".