Search a number
-
+
13310213018 = 26655106509
BaseRepresentation
bin11000110010101100…
…11011101110011010
31021100121111212201112
430121112123232122
5204224403304033
610040432020322
7650560641524
oct143126335632
937317455645
1013310213018
1157102a5053
1226b56916a2
1313417372bb
14903a3aa14
1552d7cbc48
hex31959bb9a

13310213018 has 4 divisors (see below), whose sum is σ = 19965319530. Its totient is φ = 6655106508.

The previous prime is 13310213017. The next prime is 13310213047. The reversal of 13310213018 is 81031201331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12464159449 + 846053569 = 111643^2 + 29087^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13310212984 and 13310213002.

It is not an unprimeable number, because it can be changed into a prime (13310213017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3327553253 + ... + 3327553256.

Almost surely, 213310213018 is an apocalyptic number.

13310213018 is a deficient number, since it is larger than the sum of its proper divisors (6655106512).

13310213018 is an equidigital number, since it uses as much as digits as its factorization.

13310213018 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6655106511.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 13310213018 its reverse (81031201331), we get a palindrome (94341414349).

The spelling of 13310213018 in words is "thirteen billion, three hundred ten million, two hundred thirteen thousand, eighteen".

Divisors: 1 2 6655106509 13310213018