Base | Representation |
---|---|
bin | 10011010111100111000… |
… | …110110101000000001011 |
3 | 11201020121020010120122021 |
4 | 103113213012311000023 |
5 | 133301413142040243 |
6 | 2455244013305311 |
7 | 165106654131334 |
oct | 23274706650013 |
9 | 4636536116567 |
10 | 1331022221323 |
11 | 473535387233 |
12 | 195b64795237 |
13 | 986901a9c12 |
14 | 485c968728b |
15 | 2495266e6ed |
hex | 135e71b500b |
1331022221323 has 2 divisors, whose sum is σ = 1331022221324. Its totient is φ = 1331022221322.
The previous prime is 1331022221293. The next prime is 1331022221339. The reversal of 1331022221323 is 3231222201331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1331022221323 is a prime.
It is a super-2 number, since 2×13310222213232 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1331022221383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665511110661 + 665511110662.
It is an arithmetic number, because the mean of its divisors is an integer number (665511110662).
Almost surely, 21331022221323 is an apocalyptic number.
1331022221323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331022221323 is an equidigital number, since it uses as much as digits as its factorization.
1331022221323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 1331022221323 its reverse (3231222201331), we get a palindrome (4562244422654).
The spelling of 1331022221323 in words is "one trillion, three hundred thirty-one billion, twenty-two million, two hundred twenty-one thousand, three hundred twenty-three".
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