Base | Representation |
---|---|
bin | 10011010111100111000… |
… | …110110100111111101101 |
3 | 11201020121020010120121011 |
4 | 103113213012310333231 |
5 | 133301413142040133 |
6 | 2455244013305221 |
7 | 165106654131262 |
oct | 23274706647755 |
9 | 4636536116534 |
10 | 1331022221293 |
11 | 473535387206 |
12 | 195b64795211 |
13 | 986901a9bbb |
14 | 485c9687269 |
15 | 2495266e6cd |
hex | 135e71b4fed |
1331022221293 has 2 divisors, whose sum is σ = 1331022221294. Its totient is φ = 1331022221292.
The previous prime is 1331022221281. The next prime is 1331022221323. The reversal of 1331022221293 is 3921222201331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1144810121764 + 186212099529 = 1069958^2 + 431523^2 .
It is a cyclic number.
It is not a de Polignac number, because 1331022221293 - 221 = 1331020124141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1331022221203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665511110646 + 665511110647.
It is an arithmetic number, because the mean of its divisors is an integer number (665511110647).
Almost surely, 21331022221293 is an apocalyptic number.
It is an amenable number.
1331022221293 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331022221293 is an equidigital number, since it uses as much as digits as its factorization.
1331022221293 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 31.
The spelling of 1331022221293 in words is "one trillion, three hundred thirty-one billion, twenty-two million, two hundred twenty-one thousand, two hundred ninety-three".
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