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13310234154223 = 109122112239947
BaseRepresentation
bin1100000110110000011111…
…0001110101010011101111
31202010110001002210110100121
43001230013301311103233
53221033324420413343
644150345343105411
72542430003403256
oct301540761652357
952113032713317
1013310234154223
114271925201596
1215ab7425a2267
137571c3b59586
1434030c43d79d
1518136a557aed
hexc1b07c754ef

13310234154223 has 4 divisors (see below), whose sum is σ = 13432346394280. Its totient is φ = 13188121914168.

The previous prime is 13310234154043. The next prime is 13310234154229. The reversal of 13310234154223 is 32245143201331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13310234154223 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13310234154229) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61056119865 + ... + 61056120082.

It is an arithmetic number, because the mean of its divisors is an integer number (3358086598570).

Almost surely, 213310234154223 is an apocalyptic number.

13310234154223 is a deficient number, since it is larger than the sum of its proper divisors (122112240057).

13310234154223 is a wasteful number, since it uses less digits than its factorization.

13310234154223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 122112240056.

The product of its (nonzero) digits is 51840, while the sum is 34.

Adding to 13310234154223 its reverse (32245143201331), we get a palindrome (45555377355554).

The spelling of 13310234154223 in words is "thirteen trillion, three hundred ten billion, two hundred thirty-four million, one hundred fifty-four thousand, two hundred twenty-three".

Divisors: 1 109 122112239947 13310234154223