1331024214433 has 4 divisors (see below), whose sum is σ = 1331026576560. Its totient is φ = 1331021852308.

The previous prime is 1331024214397. The next prime is 1331024214449. The reversal of 1331024214433 is 3344124201331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1331024214433 - 2²⁵ = 1330990660001 is a prime.

It is a super-2 number, since 2×1331024214433² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1331024214395 and 1331024214404.

It is not an unprimeable number, because it can be changed into a prime (1331024214463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 211398 + ... + 1645216.

It is an arithmetic number, because the mean of its divisors is an integer number (332756644140).

Almost surely, 2^{1331024214433} is an apocalyptic number.

It is an amenable number.

1331024214433 is a deficient number, since it is larger than the sum of its proper divisors (2362127).

1331024214433 is an equidigital number, since it uses as much as digits as its factorization.

1331024214433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2362126.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 1331024214433 its reverse (3344124201331), we get a palindrome (4675148415764).

The spelling of 1331024214433 in words is "one trillion, three hundred thirty-one billion, twenty-four million, two hundred fourteen thousand, four hundred thirty-three".