Base | Representation |
---|---|
bin | 10011010111100111101… |
… | …000110100011101110011 |
3 | 11201020121211220021211001 |
4 | 103113213220310131303 |
5 | 133301422432211034 |
6 | 2455244532302431 |
7 | 165110122643131 |
oct | 23274750643563 |
9 | 4636554807731 |
10 | 1331031132019 |
11 | 47353a412a46 |
12 | 195b67771a17 |
13 | 98691ca9a14 |
14 | 485ca926751 |
15 | 2495332ea14 |
hex | 135e7a34773 |
1331031132019 has 2 divisors, whose sum is σ = 1331031132020. Its totient is φ = 1331031132018.
The previous prime is 1331031132017. The next prime is 1331031132037. The reversal of 1331031132019 is 9102311301331.
It is a weak prime.
It is an emirp because it is prime and its reverse (9102311301331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1331031132019 - 21 = 1331031132017 is a prime.
It is a super-2 number, since 2×13310311320192 (a number of 25 digits) contains 22 as substring.
Together with 1331031132017, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1331031132017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665515566009 + 665515566010.
It is an arithmetic number, because the mean of its divisors is an integer number (665515566010).
Almost surely, 21331031132019 is an apocalyptic number.
1331031132019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331031132019 is an equidigital number, since it uses as much as digits as its factorization.
1331031132019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 28.
The spelling of 1331031132019 in words is "one trillion, three hundred thirty-one billion, thirty-one million, one hundred thirty-two thousand, nineteen".
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