13310321119 has 2 divisors, whose sum is σ = 13310321120. Its totient is φ = 13310321118.

The previous prime is 13310321077. The next prime is 13310321149. The reversal of 13310321119 is 91112301331.

It is a strong prime.

It is an emirp because it is prime and its reverse (91112301331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13310321119 - 2¹³ = 13310312927 is a prime.

It is a super-2 number, since 2×13310321119² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13310321093 and 13310321102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13310321149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655160559 + 6655160560.

It is an arithmetic number, because the mean of its divisors is an integer number (6655160560).

Almost surely, 2^13310321119 is an apocalyptic number.

13310321119 is a deficient number, since it is larger than the sum of its proper divisors (1).

13310321119 is an equidigital number, since it uses as much as digits as its factorization.

13310321119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486, while the sum is 25.

The spelling of 13310321119 in words is "thirteen billion, three hundred ten million, three hundred twenty-one thousand, one hundred nineteen".