Base | Representation |
---|---|
bin | 11110010000111010110011… |
… | …001001110100111110101010 |
3 | 122110021121210120000222210212 |
4 | 132100322303021310332222 |
5 | 114421234034300413002 |
6 | 1151031053002541122 |
7 | 40015310151113615 |
oct | 3620726311647652 |
9 | 573247716028725 |
10 | 133104042201002 |
11 | 3945811a897494 |
12 | 12b185565077a2 |
13 | 59368711a0822 |
14 | 24c23accd317c |
15 | 105c51cd36352 |
hex | 790eb3274faa |
133104042201002 has 8 divisors (see below), whose sum is σ = 199656121915776. Its totient is φ = 66552001562412.
The previous prime is 133104042200923. The next prime is 133104042201047. The reversal of 133104042201002 is 200102240401331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×1331040422010023 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1218023 + ... + 16361285.
It is an arithmetic number, because the mean of its divisors is an integer number (24957015239472).
Almost surely, 2133104042201002 is an apocalyptic number.
133104042201002 is a deficient number, since it is larger than the sum of its proper divisors (66552079714774).
133104042201002 is a wasteful number, since it uses less digits than its factorization.
133104042201002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19538092.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 133104042201002 its reverse (200102240401331), we get a palindrome (333206282602333).
The spelling of 133104042201002 in words is "one hundred thirty-three trillion, one hundred four billion, forty-two million, two hundred one thousand, two".
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