13310404404041 has 8 divisors (see below), whose sum is σ = 13626840714240. Its totient is φ = 12995352936288.

The previous prime is 13310404403983. The next prime is 13310404404091. The reversal of 13310404404041 is 14040440401331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13310404404041 - 2¹⁸ = 13310404141897 is a prime.

It is a super-2 number, since 2×13310404404041² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13310404403995 and 13310404404013.

It is not an unprimeable number, because it can be changed into a prime (13310404404091) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 346191161 + ... + 346229606.

It is an arithmetic number, because the mean of its divisors is an integer number (1703355089280).

Almost surely, 2^{13310404404041} is an apocalyptic number.

It is an amenable number.

13310404404041 is a deficient number, since it is larger than the sum of its proper divisors (316436310199).

13310404404041 is an equidigital number, since it uses as much as digits as its factorization.

13310404404041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 692421223.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 13310404404041 its reverse (14040440401331), we get a palindrome (27350844805372).

The spelling of 13310404404041 in words is "thirteen trillion, three hundred ten billion, four hundred four million, four hundred four thousand, forty-one".