Base | Representation |
---|---|
bin | 10011010111101000010… |
… | …010010110101100011101 |
3 | 11201020122121101110111020 |
4 | 103113220102112230131 |
5 | 133301433224121000 |
6 | 2455250001514353 |
7 | 165110314331646 |
oct | 23275022265435 |
9 | 4636577343436 |
10 | 1331042020125 |
11 | 47354557a384 |
12 | 195b6b3429b9 |
13 | 9869431c89c |
14 | 485cc15c6cd |
15 | 24954280ba0 |
hex | 135e8496b1d |
1331042020125 has 16 divisors (see below), whose sum is σ = 2214853922112. Its totient is φ = 709889077200.
The previous prime is 1331042020111. The next prime is 1331042020141. The reversal of 1331042020125 is 5210202401331.
It is not a de Polignac number, because 1331042020125 - 25 = 1331042020093 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1331042020095 and 1331042020104.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1774722319 + ... + 1774723068.
It is an arithmetic number, because the mean of its divisors is an integer number (138428370132).
Almost surely, 21331042020125 is an apocalyptic number.
1331042020125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1331042020125 is a deficient number, since it is larger than the sum of its proper divisors (883811901987).
1331042020125 is an equidigital number, since it uses as much as digits as its factorization.
1331042020125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3549445405 (or 3549445395 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 1331042020125 its reverse (5210202401331), we get a palindrome (6541244421456).
The spelling of 1331042020125 in words is "one trillion, three hundred thirty-one billion, forty-two million, twenty thousand, one hundred twenty-five".
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