13310421420433 has 2 divisors, whose sum is σ = 13310421420434. Its totient is φ = 13310421420432.

The previous prime is 13310421420407. The next prime is 13310421420473. The reversal of 13310421420433 is 33402412401331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11242528528144 + 2067892892289 = 3352988^2 + 1438017^2 .

It is an emirp because it is prime and its reverse (33402412401331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13310421420433 - 2¹³ = 13310421412241 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13310421420395 and 13310421420404.

It is not a weakly prime, because it can be changed into another prime (13310421420473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655210710216 + 6655210710217.

It is an arithmetic number, because the mean of its divisors is an integer number (6655210710217).

Almost surely, 2^{13310421420433} is an apocalyptic number.

It is an amenable number.

13310421420433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13310421420433 is an equidigital number, since it uses as much as digits as its factorization.

13310421420433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 13310421420433 its reverse (33402412401331), we get a palindrome (46712833821764).

The spelling of 13310421420433 in words is "thirteen trillion, three hundred ten billion, four hundred twenty-one million, four hundred twenty thousand, four hundred thirty-three".