Base | Representation |
---|---|
bin | 1100000110110001001011… |
… | …1100001100100101110111 |
3 | 1202010110112011011120021012 |
4 | 3001230102330030211313 |
5 | 3221034220340423112 |
6 | 44150420112542435 |
7 | 2542434436213646 |
oct | 301542274144567 |
9 | 52113464146235 |
10 | 13310421420407 |
11 | 4271a10987431 |
12 | 15ab795251a1b |
13 | 7572238a5877 |
14 | 34032926935d |
15 | 18137bbe9022 |
hex | c1b12f0c977 |
13310421420407 has 2 divisors, whose sum is σ = 13310421420408. Its totient is φ = 13310421420406.
The previous prime is 13310421420389. The next prime is 13310421420433. The reversal of 13310421420407 is 70402412401331.
13310421420407 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13310421420407 - 26 = 13310421420343 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13310421422407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655210710203 + 6655210710204.
It is an arithmetic number, because the mean of its divisors is an integer number (6655210710204).
Almost surely, 213310421420407 is an apocalyptic number.
13310421420407 is a deficient number, since it is larger than the sum of its proper divisors (1).
13310421420407 is an equidigital number, since it uses as much as digits as its factorization.
13310421420407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 32.
Adding to 13310421420407 its reverse (70402412401331), we get a palindrome (83712833821738).
The spelling of 13310421420407 in words is "thirteen trillion, three hundred ten billion, four hundred twenty-one million, four hundred twenty thousand, four hundred seven".
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