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133110012030019 is a prime number
BaseRepresentation
bin11110010001000000010110…
…111110111010110001000011
3122110022012012121022201200021
4132101000112332322301003
5114421333301034430034
61151033521221034311
740015611120612133
oct3621002676726103
9573265177281607
10133110012030019
113945a703690382
1212b19741855997
1359372b2c3482b
1424c27b7acaac3
15105c76beae6b4
hex791016fbac43

133110012030019 has 2 divisors, whose sum is σ = 133110012030020. Its totient is φ = 133110012030018.

The previous prime is 133110012029899. The next prime is 133110012030043. The reversal of 133110012030019 is 910030210011331.

It is a strong prime.

It is an emirp because it is prime and its reverse (910030210011331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133110012030019 - 217 = 133110011898947 is a prime.

It is a super-2 number, since 2×1331100120300192 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 133110012029975 and 133110012030002.

It is not a weakly prime, because it can be changed into another prime (133110012030419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66555006015009 + 66555006015010.

It is an arithmetic number, because the mean of its divisors is an integer number (66555006015010).

Almost surely, 2133110012030019 is an apocalyptic number.

133110012030019 is a deficient number, since it is larger than the sum of its proper divisors (1).

133110012030019 is an equidigital number, since it uses as much as digits as its factorization.

133110012030019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 486, while the sum is 25.

The spelling of 133110012030019 in words is "one hundred thirty-three trillion, one hundred ten billion, twelve million, thirty thousand, nineteen".