13311001332121 has 4 divisors (see below), whose sum is σ = 13319182649872. Its totient is φ = 13302820014372.

The previous prime is 13311001332113. The next prime is 13311001332131. The reversal of 13311001332121 is 12123310011331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13311001332121 - 2³ = 13311001332113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13311001332092 and 13311001332101.

It is not an unprimeable number, because it can be changed into a prime (13311001332131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4090656435 + ... + 4090659688.

It is an arithmetic number, because the mean of its divisors is an integer number (3329795662468).

Almost surely, 2^{13311001332121} is an apocalyptic number.

It is an amenable number.

13311001332121 is a deficient number, since it is larger than the sum of its proper divisors (8181317751).

13311001332121 is an equidigital number, since it uses as much as digits as its factorization.

13311001332121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8181317750.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 13311001332121 its reverse (12123310011331), we get a palindrome (25434311343452).

The spelling of 13311001332121 in words is "thirteen trillion, three hundred eleven billion, one million, three hundred thirty-two thousand, one hundred twenty-one".