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133110033120121 is a prime number
BaseRepresentation
bin11110010001000000011000…
…001111010111101101111001
3122110022012021002000012212011
4132101000120033113231321
5114421333321434320441
61151033523253045521
740015611465101251
oct3621003017275571
9573265232005764
10133110033120121
113945a714585712
1212b197489268a1
1359372b740a195
1424c27ba81a961
15105c76dc78581
hex7910183d7b79

133110033120121 has 2 divisors, whose sum is σ = 133110033120122. Its totient is φ = 133110033120120.

The previous prime is 133110033120109. The next prime is 133110033120167. The reversal of 133110033120121 is 121021330011331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 66591083632896 + 66518949487225 = 8160336^2 + 8155915^2 .

It is a cyclic number.

It is not a de Polignac number, because 133110033120121 - 25 = 133110033120089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133110033120092 and 133110033120101.

It is not a weakly prime, because it can be changed into another prime (133110033130121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66555016560060 + 66555016560061.

It is an arithmetic number, because the mean of its divisors is an integer number (66555016560061).

Almost surely, 2133110033120121 is an apocalyptic number.

It is an amenable number.

133110033120121 is a deficient number, since it is larger than the sum of its proper divisors (1).

133110033120121 is an equidigital number, since it uses as much as digits as its factorization.

133110033120121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 133110033120121 its reverse (121021330011331), we get a palindrome (254131363131452).

The spelling of 133110033120121 in words is "one hundred thirty-three trillion, one hundred ten billion, thirty-three million, one hundred twenty thousand, one hundred twenty-one".