Base | Representation |
---|---|
bin | 1100000110110011101110… |
… | …0001100011011110110011 |
3 | 1202010112021121100221101211 |
4 | 3001230323201203132303 |
5 | 3221042114142132011 |
6 | 44151011434340551 |
7 | 2542460344500604 |
oct | 301547341433663 |
9 | 52115247327354 |
10 | 13311102302131 |
11 | 42722302589a7 |
12 | 15ab94528a757 |
13 | 75730197cc6a |
14 | 340391867dab |
15 | 1813bb891b21 |
hex | c1b3b8637b3 |
13311102302131 has 2 divisors, whose sum is σ = 13311102302132. Its totient is φ = 13311102302130.
The previous prime is 13311102302093. The next prime is 13311102302137. The reversal of 13311102302131 is 13120320111331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13311102302131 - 29 = 13311102301619 is a prime.
It is a super-2 number, since 2×133111023021312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13311102302137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655551151065 + 6655551151066.
It is an arithmetic number, because the mean of its divisors is an integer number (6655551151066).
Almost surely, 213311102302131 is an apocalyptic number.
13311102302131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13311102302131 is an equidigital number, since it uses as much as digits as its factorization.
13311102302131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 13311102302131 its reverse (13120320111331), we get a palindrome (26431422413462).
The spelling of 13311102302131 in words is "thirteen trillion, three hundred eleven billion, one hundred two million, three hundred two thousand, one hundred thirty-one".
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