13311103300331 has 4 divisors (see below), whose sum is σ = 13336652443464. Its totient is φ = 13285554157200.

The previous prime is 13311103300303. The next prime is 13311103300337. The reversal of 13311103300331 is 13300330111331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13311103300331 is a prime.

It is a super-4 number, since 4×13311103300331⁴ (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13311103300297 and 13311103300306.

It is not an unprimeable number, because it can be changed into a prime (13311103300337) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12774570785 + ... + 12774571826.

It is an arithmetic number, because the mean of its divisors is an integer number (3334163110866).

Almost surely, 2^{13311103300331} is an apocalyptic number.

13311103300331 is a deficient number, since it is larger than the sum of its proper divisors (25549143133).

13311103300331 is an equidigital number, since it uses as much as digits as its factorization.

13311103300331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25549143132.

The product of its (nonzero) digits is 729, while the sum is 23.

Adding to 13311103300331 its reverse (13300330111331), we get a palindrome (26611433411662).

The spelling of 13311103300331 in words is "thirteen trillion, three hundred eleven billion, one hundred three million, three hundred thousand, three hundred thirty-one".