Base | Representation |
---|---|
bin | 10011010111101100011… |
… | …001111100110111010101 |
3 | 11201020211102102010011111 |
4 | 103113230121330313111 |
5 | 133302103421322331 |
6 | 2455300510535021 |
7 | 165112113560212 |
oct | 23275431746725 |
9 | 4636742363144 |
10 | 1331111120341 |
11 | 4735805863a2 |
12 | 195b8a507471 |
13 | 986a57349a2 |
14 | 485d73c8b09 |
15 | 2495a37edb1 |
hex | 135ec67cdd5 |
1331111120341 has 2 divisors, whose sum is σ = 1331111120342. Its totient is φ = 1331111120340.
The previous prime is 1331111120309. The next prime is 1331111120371. The reversal of 1331111120341 is 1430211111331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 670392500625 + 660718619716 = 818775^2 + 812846^2 .
It is a cyclic number.
It is not a de Polignac number, because 1331111120341 - 25 = 1331111120309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1331111120371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665555560170 + 665555560171.
It is an arithmetic number, because the mean of its divisors is an integer number (665555560171).
Almost surely, 21331111120341 is an apocalyptic number.
It is an amenable number.
1331111120341 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331111120341 is an equidigital number, since it uses as much as digits as its factorization.
1331111120341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 22.
Adding to 1331111120341 its reverse (1430211111331), we get a palindrome (2761322231672).
The spelling of 1331111120341 in words is "one trillion, three hundred thirty-one billion, one hundred eleven million, one hundred twenty thousand, three hundred forty-one".
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