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13311140011027 is a prime number
BaseRepresentation
bin1100000110110011110111…
…0001011001110000010011
31202010112101020022202021121
43001230331301121300103
53221042203320323102
644151015302503111
72542461313144225
oct301547561316023
952115336282247
1013311140011027
11427224a574181
1215ab955a34a97
13757309723a11
14340396882415
151813bed3eb37
hexc1b3dc59c13

13311140011027 has 2 divisors, whose sum is σ = 13311140011028. Its totient is φ = 13311140011026.

The previous prime is 13311140011007. The next prime is 13311140011051. The reversal of 13311140011027 is 72011004111331.

13311140011027 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13311140011027 - 27 = 13311140010899 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13311140010992 and 13311140011010.

It is not a weakly prime, because it can be changed into another prime (13311140011007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655570005513 + 6655570005514.

It is an arithmetic number, because the mean of its divisors is an integer number (6655570005514).

Almost surely, 213311140011027 is an apocalyptic number.

13311140011027 is a deficient number, since it is larger than the sum of its proper divisors (1).

13311140011027 is an equidigital number, since it uses as much as digits as its factorization.

13311140011027 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 25.

Adding to 13311140011027 its reverse (72011004111331), we get a palindrome (85322144122358).

The spelling of 13311140011027 in words is "thirteen trillion, three hundred eleven billion, one hundred forty million, eleven thousand, twenty-seven".