Base | Representation |
---|---|
bin | 1100000110110011110111… |
… | …0001011001110000101011 |
3 | 1202010112101020022202022111 |
4 | 3001230331301121300223 |
5 | 3221042203320323201 |
6 | 44151015302503151 |
7 | 2542461313144261 |
oct | 301547561316053 |
9 | 52115336282274 |
10 | 13311140011051 |
11 | 427224a5741a3 |
12 | 15ab955a34ab7 |
13 | 757309723a2c |
14 | 340396882431 |
15 | 1813bed3eb51 |
hex | c1b3dc59c2b |
13311140011051 has 2 divisors, whose sum is σ = 13311140011052. Its totient is φ = 13311140011050.
The previous prime is 13311140011027. The next prime is 13311140011063. The reversal of 13311140011051 is 15011004111331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13311140011051 - 27 = 13311140010923 is a prime.
It is not a weakly prime, because it can be changed into another prime (13311140711051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655570005525 + 6655570005526.
It is an arithmetic number, because the mean of its divisors is an integer number (6655570005526).
Almost surely, 213311140011051 is an apocalyptic number.
13311140011051 is a deficient number, since it is larger than the sum of its proper divisors (1).
13311140011051 is an equidigital number, since it uses as much as digits as its factorization.
13311140011051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 180, while the sum is 22.
Adding to 13311140011051 its reverse (15011004111331), we get a palindrome (28322144122382).
The spelling of 13311140011051 in words is "thirteen trillion, three hundred eleven billion, one hundred forty million, eleven thousand, fifty-one".
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