13311200042431 has 4 divisors (see below), whose sum is σ = 13311207492192. Its totient is φ = 13311192592672.

The previous prime is 13311200042401. The next prime is 13311200042443. The reversal of 13311200042431 is 13424000211331.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13311200042431 - 2⁷ = 13311200042303 is a prime.

It is a super-2 number, since 2×13311200042431² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13311200042396 and 13311200042405.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13311200042401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 736410 + ... + 5211976.

It is an arithmetic number, because the mean of its divisors is an integer number (3327801873048).

Almost surely, 2^{13311200042431} is an apocalyptic number.

13311200042431 is a deficient number, since it is larger than the sum of its proper divisors (7449761).

13311200042431 is an equidigital number, since it uses as much as digits as its factorization.

13311200042431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7449760.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13311200042431 its reverse (13424000211331), we get a palindrome (26735200253762).

The spelling of 13311200042431 in words is "thirteen trillion, three hundred eleven billion, two hundred million, forty-two thousand, four hundred thirty-one".