Base | Representation |
---|---|
bin | 1100000110110100000110… |
… | …0010111100011111010011 |
3 | 1202010112112122110200120212 |
4 | 3001231001202330133103 |
5 | 3221042321023030003 |
6 | 44151025443554335 |
7 | 2542463012303525 |
oct | 301550142743723 |
9 | 52115478420525 |
10 | 13311203330003 |
11 | 4272282291707 |
12 | 15ab97308b9ab |
13 | 757319893577 |
14 | 3403a1045a15 |
15 | 1813c569add8 |
hex | c1b418bc7d3 |
13311203330003 has 2 divisors, whose sum is σ = 13311203330004. Its totient is φ = 13311203330002.
The previous prime is 13311203329943. The next prime is 13311203330021. The reversal of 13311203330003 is 30003330211331.
13311203330003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13311203330003 - 28 = 13311203329747 is a prime.
It is a super-2 number, since 2×133112033300032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13311203330083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655601665001 + 6655601665002.
It is an arithmetic number, because the mean of its divisors is an integer number (6655601665002).
Almost surely, 213311203330003 is an apocalyptic number.
13311203330003 is a deficient number, since it is larger than the sum of its proper divisors (1).
13311203330003 is an equidigital number, since it uses as much as digits as its factorization.
13311203330003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 23.
Adding to 13311203330003 its reverse (30003330211331), we get a palindrome (43314533541334).
The spelling of 13311203330003 in words is "thirteen trillion, three hundred eleven billion, two hundred three million, three hundred thirty thousand, three".
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