133112100000000 has 1944 divisors, whose sum is σ = 515031845678560. Its totient is φ = 30412800000000.

The previous prime is 133112099999993. The next prime is 133112100000067. The reversal of 133112100000000 is 1211331.

It is a super-4 number, since 4×133112100000000⁴ (a number of 58 digits) contains 4444 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 215 ways as a sum of consecutive naturals, for example, 689699999904 + ... + 689700000096.

Almost surely, 2^{133112100000000} is an apocalyptic number.

133112100000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133112100000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (257515922839280).

133112100000000 is an abundant number, since it is smaller than the sum of its proper divisors (381919745678560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133112100000000 is an frugal number, since it uses more digits than its factorization.

133112100000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 293 (or 233 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 133112100000000 its reverse (1211331), we get a palindrome (133112101211331).

The spelling of 133112100000000 in words is "one hundred thirty-three trillion, one hundred twelve billion, one hundred million", and thus it is an aban number.