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13311210401341 is a prime number
BaseRepresentation
bin1100000110110100000111…
…1101111010111000111101
31202010112120010202221122021
43001231001331322320331
53221042324330320331
644151030255320141
72542463126354626
oct301550175727075
952115503687567
1013311210401341
114272286281496
1215ab975520051
1375731b19b0a8
143403a1d66a4d
151813c60e6211
hexc1b41f7ae3d

13311210401341 has 2 divisors, whose sum is σ = 13311210401342. Its totient is φ = 13311210401340.

The previous prime is 13311210401329. The next prime is 13311210401393. The reversal of 13311210401341 is 14310401211331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7230473614116 + 6080736787225 = 2688954^2 + 2465915^2 .

It is a cyclic number.

It is not a de Polignac number, because 13311210401341 - 223 = 13311202012733 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13311210401441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655605200670 + 6655605200671.

It is an arithmetic number, because the mean of its divisors is an integer number (6655605200671).

Almost surely, 213311210401341 is an apocalyptic number.

It is an amenable number.

13311210401341 is a deficient number, since it is larger than the sum of its proper divisors (1).

13311210401341 is an equidigital number, since it uses as much as digits as its factorization.

13311210401341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 13311210401341 its reverse (14310401211331), we get a palindrome (27621611612672).

The spelling of 13311210401341 in words is "thirteen trillion, three hundred eleven billion, two hundred ten million, four hundred one thousand, three hundred forty-one".