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133112211293 is a prime number
BaseRepresentation
bin111101111111000011…
…0110010011101011101
3110201120211002221220202
41323332012302131131
54140103211230133
6141052332353245
712421434061445
oct1737606623535
9421524087822
10133112211293
11514a8411586
122196b015825
13c7248b6a89
14662a961125
1536e11c02e8
hex1efe1b275d

133112211293 has 2 divisors, whose sum is σ = 133112211294. Its totient is φ = 133112211292.

The previous prime is 133112211257. The next prime is 133112211403. The reversal of 133112211293 is 392112211331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99715745284 + 33396466009 = 315778^2 + 182747^2 .

It is an emirp because it is prime and its reverse (392112211331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133112211293 - 212 = 133112207197 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133112211593) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66556105646 + 66556105647.

It is an arithmetic number, because the mean of its divisors is an integer number (66556105647).

Almost surely, 2133112211293 is an apocalyptic number.

It is an amenable number.

133112211293 is a deficient number, since it is larger than the sum of its proper divisors (1).

133112211293 is an equidigital number, since it uses as much as digits as its factorization.

133112211293 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1944, while the sum is 29.

The spelling of 133112211293 in words is "one hundred thirty-three billion, one hundred twelve million, two hundred eleven thousand, two hundred ninety-three".