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133113001345 = 537719529737
BaseRepresentation
bin111101111111000100…
…1110011010110000001
3110201120212121002122221
41323332021303112001
54140103412020340
6141052401331041
712421443562012
oct1737611632601
9421525532587
10133113001345
11514a8901115
122196b336a81
13c724b0256c
14662aac9009
1536e12c944a
hex1efe273581

133113001345 has 8 divisors (see below), whose sum is σ = 164052780264. Its totient is φ = 103612281984.

The previous prime is 133113001327. The next prime is 133113001369. The reversal of 133113001345 is 543100311331.

It can be written as a sum of positive squares in 4 ways, for example, as 26303649856 + 106809351489 = 162184^2 + 326817^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 133113001345 - 211 = 133112999297 is a prime.

It is a super-2 number, since 2×1331130013452 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 359764684 + ... + 359765053.

It is an arithmetic number, because the mean of its divisors is an integer number (20506597533).

Almost surely, 2133113001345 is an apocalyptic number.

It is an amenable number.

133113001345 is a deficient number, since it is larger than the sum of its proper divisors (30939778919).

133113001345 is an equidigital number, since it uses as much as digits as its factorization.

133113001345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 719529779.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 133113001345 its reverse (543100311331), we get a palindrome (676213312676).

The spelling of 133113001345 in words is "one hundred thirty-three billion, one hundred thirteen million, one thousand, three hundred forty-five".

Divisors: 1 5 37 185 719529737 3597648685 26622600269 133113001345